ANSWER: The rules you understand for instance the you to definitely you offer use simply when the charge can be thought of as a continuous liquid that can give in itself from any epidermis, no matter how high, and have now no occurrence. However, an instance like you establish, that have 5 a lot of electrons is actually not a way instance a liquid and i also manage guess that anything from 5-0 to help you 0-5 could be the shipments more than a period. In principle, the five electrons create strategy themselves to make sure that for every is actually just like the at a distance in the almost every other 4 to, but truth be told there would not be a new for example shipping.
QUESTION: Will it be you’ll in order to suspend a keen electron through electrostatic levitation inside a consistent magnetized profession? Of course the newest current try diminished enough so the electrostatic push toward electron was below the new force on account of the fresh new electron’s weight perform the new electron upcoming feel a good ‘fall’ due in order to gravity?
I am inquiring this simply because I’m curious in the event that setting a positron during the an effective uniform magnetized community (in the vacuum pressure) and you will decreasing the voltage to a very brief really worth making sure that the latest electrostatic push is lower than the weight would produce a beneficial positron so you can together with experience an effective ‘fall’. Assuming they performed sense a trip it may be ascertained if this perform fall upwards or downward.
Because of the inertial bulk I am talking about this new ratio of one’s push you affect it split of the the velocity, put another way their effectiveness becoming accelerated
I am 17 years old and in great britain planning to study physics at university from inside the sep and you can was just curious about which once the one of our subject areas this season is actually electricity phenomena and you will we talked about millikan’s oil miss try out and that featured an equivalent brand of suspension when the electrostatic force and you can push because of gravity was basically well-balanced.
Now, we know to help you over the top accuracy the inertial bulk of an excellent positron is equivalent to the latest inertial size from an enthusiastic electron
ANSWER: It is always nice to see young folks asking interesting questions. First, I need to correct one thing: everywhere you refer to a “magnetic field” you should say “electric field”; a magnetic field exerts no force on a charge at rest which is what you want to observe, la Millikan. (A more correct way, relativistically, to say this would be that they have equal momenta for equal speeds.) I believe it is true that nobody has ever “weighed” a positron by measuring the force it experiences in a gravitational field. But, if the gravitational mass were different from the inertial mass, this would fly in the face of the theory of general relativity. But, let’s talk about the feasibility of your experiment. The mass of an electron is about 10 -30 kg so its weight would be about 10 -29 N (taking g?10 m/s 2 ). The electron charge is about 1.6×10 -19 C and so the electric field required to levitate an electron would be 10 -29 /1.6×10 -19 ?6×10 -11 V/m. Suppose we use a parallel plate capacitor to create this field. The charge density ? on a plate with field E is about ?=?0E?10 -11 x6x10 -11 =6×10 -22 C/m 2 which would correspond to an electron density on the plates of about 6×10 -22 /1.6×10 -19 ?0.004 electrons/m 2 ! This would correspond to about one electron for every 250 square meters! That would not give a very uniform field would it? There is no such thing as a uniform surface charge density because charges in nature do not comprise a continuous fluid; so really tiny uniform fields are not possible. I did all that just for the fun of it, but there is an even more serious considerationthe earth itself has an electric field near the surface of typically 100 V/m pointing down, so an electron would be repelled upward. To do your experiment you would have Russian dating to get rid of that field and I do not believe that it would be possible to be assured that you could make the residual field much less than your 6×10 -11 V/m. Back to the drawing board! Keep asking those hard and interesting questions, though, and good luck with your university studies.